[JEE Main 2002] if a b c are distinct positive reals with a 2 b 2 c
If $a,b,c$ are distinct positive reals with $a^2+b^2+c^2=1$, then $ab+bc+ca$ is
(a) less than $1$
(b) equal to $1$
(c) greater than $1$
(d) any real number
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (a) less than $1$
$ab+bc+ca<a^2+b^2+c^2=1$ because $a,b,c$ are distinct (strict AM-type inequality).
JEE Main 2002 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.