[JEE Advanced 1984] If $a<b<c<d$, the roots of $(x-a)(x-c)+2(x-b)(x-d)=0$ are real and distinct.
If $a<b<c<d$, the roots of $(x-a)(x-c)+2(x-b)(x-d)=0$ are real and distinct.
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· 1mo ago
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Answer: True.
$f(a)>0,\ f(b)<0,\ f(d)>0$, so there is a root in $(a,b)$ and another in $(b,d)$ — two real distinct roots.
JEE Advanced 1984 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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