[JEE Advanced 1979] If $l,m,n$ are real and $l\ne m$, then the roots of $(l-m)x^2-5(l+m)x-2(l-m)=0$ are
If $l,m,n$ are real and $l\ne m$, then the roots of $(l-m)x^2-5(l+m)x-2(l-m)=0$ are
(a) real and equal
(b) complex
(c) real and unequal
(d) none of these
1 Answer
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· 1mo ago
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Correct answer: (c) real and unequal
Discriminant $=25(l+m)^2+8(l-m)^2>0$ (with $l\ne m$), so the roots are real and unequal.
JEE Advanced 1979 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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