[JEE Main 2005] if omega z z i3 and omega 1 then z lies on
If $\omega=\dfrac{z}{z-\frac i3}$ and $|\omega|=1$, then $z$ lies on
(a) an ellipse
(b) a circle
(c) a straight line
(d) a parabola
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (c) a straight line
$|z|=\left|z-\frac i3\right|$ means $z$ is equidistant from $0$ and $\frac i3$ — the perpendicular bisector, a straight line.
JEE Main 2005 · Complex Numbers — verified solution by the Vidaara Team.
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