[JEE Advanced 2004] if one root is the square of the other root of x 2 px
If one root is the square of the other root of $x^2+px+q=0$, then
(a) $p^3-q(3p-1)+q^2=0$
(b) $p^3-q(3p+1)+q^2=0$
(c) $p^3+q(3p-1)+q^2=0$
(d) $p^3+q(3p+1)+q^2=0$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (a) $p^3-q(3p-1)+q^2=0$
Roots $\alpha,\alpha^2$: $(-p)^3=(\alpha+\alpha^2)^3=q+3q(-p)+q^2$, giving $p^3-q(3p-1)+q^2=0$.
JEE Advanced 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.