[JEE Main 2004] If one root of $x^2+px+12=0$ is $4$, while $x^2+px+q=0$ has equal roots, then $q$ is
If one root of $x^2+px+12=0$ is $4$, while $x^2+px+q=0$ has equal roots, then $q$ is
(a) $4$
(b) $12$
(c) $3$
(d) $\frac{49}4$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
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Correct answer: (d) $\frac{49}4$
$16+4p+12=0\Rightarrow p=-7$; equal roots $\Rightarrow q=\frac{p^2}4=\frac{49}4$.
JEE Main 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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