[JEE Advanced 1999] If the roots of $x^2-2ax+a^2+a-3=0$ are real and less than $3$, then
If the roots of $x^2-2ax+a^2+a-3=0$ are real and less than $3$, then
(a) $a<2$
(b) $2\le a\le3$
(c) $3<a\le4$
(d) $a>4$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 0
Correct answer: (a) $a<2$
$D\ge0\Rightarrow a\le3$; $f(3)=a^2-5a+6>0\Rightarrow a<2$ or $a>3$; vertex $a<3$. Together $a<2$.
JEE Advanced 1999 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.