[JEE Main 2006] If the roots of $x^2+px+q=0$ are $\tan30^\circ$ and $\tan15^\circ$, then $2+q-p$ is
If the roots of $x^2+px+q=0$ are $\tan30^\circ$ and $\tan15^\circ$, then $2+q-p$ is
(a) $2$
(b) $3$
(c) $0$
(d) $1$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 0
Correct answer: (b) $3$
$\tan45^\circ=\frac{\tan30^\circ+\tan15^\circ}{1-\tan30^\circ\tan15^\circ}=1$, so $-p+q=1$; thus $2+q-p=3$.
JEE Main 2006 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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