[JEE Advanced 2004] if x 2 2ax 10 3a 0 for all real x then a lies
If $x^2+2ax+10-3a>0$ for all real $x$, then $a$ lies in
(a) $a<-5$
(b) $-5<a<2$
(c) $a>5$
(d) $2<a<5$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (b) $-5<a<2$
Need discriminant $<0$: $4a^2-4(10-3a)<0\Rightarrow(a+5)(a-2)<0\Rightarrow-5<a<2$.
JEE Advanced 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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