JEE PYQ

[JEE Advanced 1980] If $x^2+px+1$ is a factor of $ax^3+bx+c$, then

VAVidaara Admin Asked 1mo ago 1 views 1 answer

If $x^2+px+1$ is a factor of $ax^3+bx+c$, then

(a) $a^2+c^2=-ab$
(b) $a^2-c^2=-ab$
(c) $a^2-c^2=ab$
(d) none of these

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Correct answer: (c) $a^2-c^2=ab$

Writing $ax^3+bx+c=(x^2+px+1)(ax+k)$ and matching gives $c=-ap$ and $b=(a^2-c^2)/a$, so $a^2-c^2=ab$.

JEE Advanced 1980 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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