[JEE Main 2002] if z 4 z 2 its solution is
If $|z-4|<|z-2|$, its solution is
(a) $\operatorname{Re}(z)>0$
(b) $\operatorname{Re}(z)<0$
(c) $\operatorname{Re}(z)>3$
(d) $\operatorname{Re}(z)>2$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (c) $\operatorname{Re}(z)>3$
Closer to $4$ than to $2$ means right of the bisector $x=3$: $\operatorname{Re}(z)>3$.
JEE Main 2002 · Complex Numbers — verified solution by the Vidaara Team.
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