[JEE Main 2009] if z 4z 2 then the maximum value of z is
If $\left|z-\dfrac4z\right|=2$, then the maximum value of $|z|$ is
(a) $\sqrt5+1$
(b) $2$
(c) $2+\sqrt2$
(d) $\sqrt3+1$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (a) $\sqrt5+1$
$|z|-\frac4{|z|}\le\left|z-\frac4z\right|=2$, so with $r=|z|$, $r^2-2r-4\le0\Rightarrow r\le1+\sqrt5$.
JEE Main 2009 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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