[JEE Main 2014] if z is complex with z 2 then the minimum value of z 12
If $z$ is complex with $|z|\ge2$, then the minimum value of $\left|z+\frac12\right|$
(a) is strictly greater than $\frac52$
(b) is strictly greater than $\frac32$ but less than $\frac52$
(c) is equal to $\frac52$
(d) lies in the interval $(1,2)$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (d) lies in the interval $(1,2)$
Minimum distance from $-\frac12$ to the region $|z|\ge2$ is $2-\frac12=\frac32$, which lies in $(1,2)$.
JEE Main 2014 · Complex Numbers — verified solution by the Vidaara Team.
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