[JEE Main 2002] if z omega are non zero with z omega 1 and arg z arg
If $z,\omega$ are non-zero with $|z\omega|=1$ and $\arg z-\arg\omega=\frac\pi2$, then $\bar z\omega$ equals
(a) $-i$
(b) $1$
(c) $-1$
(d) $i$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (a) $-i$
$|\bar z\omega|=|z||\omega|=1$ and $\arg(\bar z\omega)=-\arg z+\arg\omega=-\frac\pi2$, so $\bar z\omega=e^{-i\pi/2}=-i$.
JEE Main 2002 · Complex Numbers — verified solution by the Vidaara Team.
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