[JEE Advanced 1983] if z x iy and omega 1 iz z i then omega 1 implies
If $z=x+iy$ and $\omega=\dfrac{1-iz}{z-i}$, then $|\omega|=1$ implies that
(a) $z$ lies on the imaginary axis
(b) $z$ lies on the real axis
(c) $z$ lies on the unit circle
(d) none of these
1 Answer
Correct answer: (b) $z$ lies on the real axis
$1-iz=-i(z+i)$, so $|\omega|=\frac{|z+i|}{|z-i|}=1\Rightarrow|z+i|=|z-i|\Rightarrow z$ is on the real axis.
JEE Advanced 1983 · Complex Numbers — verified solution by the Vidaara Team.
No comments yet — start the discussion.