imo class 12 application of derivatives

A local manufacturer in Delhi calculates its daily profit P(x) in rupees by P(x) = -5x² + 100x - 150, where x is items sold. Find the maximum daily profit.

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A local manufacturer in Delhi calculates its daily profit P(x) in rupees by P(x) = -5x² + 100x - 150, where x is items sold. Find the maximum daily profit.

  • A. ₹200
  • B. ₹250
  • C. ₹350
  • D. ₹500

Answer: C) ₹350

Explanation: P'(x) = -10x + 100 = 0 → x = 10. Max Profit = P(10) = -5(100) + 1000 - 150 = -500 + 1000 - 150 = ₹350.

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