Find the interval in which the function f(x) = x³ - 12x² + 36x + 17 is strictly increasing. A. (2, 6) B. (-∞, 2) ∪ (6, ∞) C. (-6, 2) D. (-∞, -6) ∪ (-2, ∞) Answer: B) (-∞, 2) ∪ (6, ∞) Explanation: f'(x) = 3x² - 24x + 36 = 3(x - 2)(x - 6). For f'(x) > 0, x 6. Interval is (-∞, 2) ∪ (6, ∞).

imo class 12 application of derivatives

Find the interval in which the function f(x) = x³ - 12x² + 36x + 17 is strictly increasing.

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Find the interval in which the function f(x) = x³ - 12x² + 36x + 17 is strictly increasing.

Answer: B) (-∞, 2) ∪ (6, ∞)

Explanation: f'(x) = 3x² - 24x + 36 = 3(x - 2)(x - 6). For f'(x) > 0, x < 2 or x > 6. Interval is (-∞, 2) ∪ (6, ∞).