An edge of a variable cube is increasing at the rate of 10 cm/s. How fast is the surface area increasing when the edge is 5 cm long? A. 600 cm²/s B. 300 cm²/s C. 1200 cm²/s D. 150 cm²/s Answer: A) 600 cm²/s Explanation: Surface Area S = 6x². dS/dt = 12x(dx/dt). Given dx/dt = 10 and x = 5. dS/dt = 12(5)(10) = 600 cm²/s.

imo class 12 application of derivatives

An edge of a variable cube is increasing at the rate of 10 cm/s. How fast is the surface area increasing when the edge is 5 cm long?

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An edge of a variable cube is increasing at the rate of 10 cm/s. How fast is the surface area increasing when the edge is 5 cm long?

Answer: A) 600 cm²/s

Explanation: Surface Area S = 6x². dS/dt = 12x(dx/dt). Given dx/dt = 10 and x = 5. dS/dt = 12(5)(10) = 600 cm²/s.