The function f(x) = 2x³ - 3x² - 36x + 7 is strictly decreasing in the interval:
The function f(x) = 2x³ - 3x² - 36x + 7 is strictly decreasing in the interval:
- A. (-∞, -2)
- B. (-2, 3)
- C. (3, ∞)
- D. (-3, 2)
Answer: B) (-2, 3)
Explanation: f'(x) = 6x² - 6x - 36 = 6(x² - x - 6) = 6(x - 3)(x + 2). For strictly decreasing, f'(x) < 0, which happens in the interval (-2, 3).
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