The slope of the tangent to the curve y = √(3x + 1) at the point whose x-coordinate is 1 is:
The slope of the tangent to the curve y = √(3x + 1) at the point whose x-coordinate is 1 is:
- A. 3/4
- B. 1/4
- C. 1/2
- D. 3/2
Answer: A) 3/4
Explanation: dy/dx = 3/(2√(3x + 1)). At x = 1, dy/dx = 3/(2√4) = 3/4.
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