The normal to the curve y = x² − 4x + 3 at x = 2 passes through the point:
The normal to the curve y = x² − 4x + 3 at x = 2 passes through the point:
- A. (1, 2)
- B. (0, 5)
- C. (3, 1)
- D. (2, 4)
Answer: D) (2, 4)
Explanation: dy/dx = 2x − 4 = 0 at x = 2, so the tangent is horizontal and the normal is the vertical line x = 2, which passes through (2, 4).
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