imo class 12 application of derivatives

The minimum value of f(x) = x² - 4x + 10 is:

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The minimum value of f(x) = x² - 4x + 10 is:

  • A. 10
  • B. 4
  • C. 6
  • D. 2

Answer: C) 6

Explanation: f'(x) = 2x - 4 = 0 → x = 2. Since f''(x) = 2 > 0, it is a minimum. Minimum value f(2) = 4 - 8 + 10 = 6.

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