The maximum value of the function f(x) = x³ − 3x on the interval [0, 2] is:
The maximum value of the function f(x) = x³ − 3x on the interval [0, 2] is:
- A. 2
- B. 0
- C. 1
- D. −2
Answer: A) 2
Explanation: f'(x) = 3x² − 3 = 3(x − 1)(x + 1). Critical points in [0, 2]: x = 1. f(0) = 0, f(1) = −2, f(2) = 8 − 6 = 2. Maximum is 2 at x = 2.
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