Of all the rectangles of a given perimeter, the one with the greatest area is a: A. Square B. Rectangle with length twice breadth C. Rectangle with length thrice breadth D. Rhombus Answer: A) Square Explanation: Let perimeter be P = 2(l+b). Area A = l(P/2 - l). A' = P/2 - 2l = 0 implies l = P/4, which means b = P/4. The rectangle is a square.

imo class 12 application of derivatives

Of all the rectangles of a given perimeter, the one with the greatest area is a:

VAVidaara Admin Asked 6d ago 0 views 0 answers

Of all the rectangles of a given perimeter, the one with the greatest area is a:

Answer: A) Square

Explanation: Let perimeter be P = 2(l+b). Area A = l(P/2 - l). A' = P/2 - 2l = 0 implies l = P/4, which means b = P/4. The rectangle is a square.