The equation of the tangent to the curve y = x² − 3x + 2 at the point where x = 2 is: A. x − y = 0 B. x + y = 2 C. x − y = 2 D. x + y = 0 Answer: C) x − y = 2 Explanation: When x = 2, y = 4 − 6 + 2 = 0. dy/dx = 2x − 3, at x = 2 slope = 1. Tangent: y − 0 = 1(x − 2) → y = x − 2 → x − y = 2.

imo class 12 application of derivatives

The equation of the tangent to the curve y = x² − 3x + 2 at the point where x = 2 is:

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The equation of the tangent to the curve y = x² − 3x + 2 at the point where x = 2 is:

Answer: C) x − y = 2

Explanation: When x = 2, y = 4 − 6 + 2 = 0. dy/dx = 2x − 3, at x = 2 slope = 1. Tangent: y − 0 = 1(x − 2) → y = x − 2 → x − y = 2.