What is the area enclosed between the parabola y² = 4x and the line y = x? A. 8/3 B. 4/3 C. 16/3 D. 2/3 Answer: A) 8/3 Explanation: Intersections: x² = 4x → x=0, 4. Area = ∫(0 to 4) (2√x − x) dx = [4/3 x^(3/2) − x²/2] = 32/3 − 8 = 8/3 sq units.

imo class 12 application of integrals

What is the area enclosed between the parabola y² = 4x and the line y = x?

VAVidaara Admin Asked 6d ago 0 views 0 answers

What is the area enclosed between the parabola y² = 4x and the line y = x?

Answer: A) 8/3

Explanation: Intersections: x² = 4x → x=0, 4. Area = ∫(0 to 4) (2√x − x) dx = [4/3 x^(3/2) − x²/2] = 32/3 − 8 = 8/3 sq units.