Using integration, the area of the triangle with vertices (0,0), (2,0) and (0,3) is:

Using integration, the area of the triangle with vertices (0,0), (2,0) and (0,3) is:

• A. 3 sq units
• B. 6 sq units
• C. 2 sq units
• D. 1 sq unit

Answer: A) 3 sq units

Explanation: Line through (2,0) and (0,3) is x/2 + y/3 = 1 → y = 3(1 − x/2). Area = ∫[0 to 2] 3(1 − x/2) dx = 3[x − x²/4]₀² = 3(2 − 1) = 3 sq units.