What is the area enclosed by the ellipse x²/16 + y²/9 = 1?
What is the area enclosed by the ellipse x²/16 + y²/9 = 1?
- A. 12π
- B. 25π
- C. 16π
- D. 9π
Answer: A) 12π
Explanation: Area of ellipse x²/a² + y²/b² = 1 is πab. Here a = 4, b = 3. Area = π(4)(3) = 12π sq units.
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