For the function f(x) = x³ − 6x² + ax + b, it is given f(1) = f(3) = 0. The values of a and b are:
For the function f(x) = x³ − 6x² + ax + b, it is given f(1) = f(3) = 0. The values of a and b are:
- A. a = 11, b = −6
- B. a = −11, b = 6
- C. a = 6, b = −11
- D. a = −6, b = 11
Answer: A) a = 11, b = −6
Explanation: f(1) = 1 − 6 + a + b = 0 → a + b = 5. f(3) = 27 − 54 + 3a + b = 0 → 3a + b = 27. Solving: 2a = 22 → a = 11, b = −6.
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