Consider f(x) = |x − 1| + |x − 2|. The number of points where f(x) is not differentiable is:
Consider f(x) = |x − 1| + |x − 2|. The number of points where f(x) is not differentiable is:
- A. 0
- B. 1
- C. 2
- D. 3
Answer: C) 2
Explanation: The sum of absolute value functions has sharp turns at the roots of the expressions inside the modulus. Here, the roots are x = 1 and x = 2. So, it is not differentiable at 2 points.
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