Find dy/dx if y = log(sec x + tan x).
Find dy/dx if y = log(sec x + tan x).
- A. sec x
- B. tan x
- C. sec x tan x
- D. sec²x
Answer: A) sec x
Explanation: dy/dx = (1 / (sec x + tan x)) × d/dx(sec x + tan x) = (1 / (sec x + tan x)) × (sec x tan x + sec²x) = sec x(tan x + sec x) / (sec x + tan x) = sec x.
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