The number of points in (0, 2) where f(x) = |x − 1| + |x − 3| is not differentiable is:
The number of points in (0, 2) where f(x) = |x − 1| + |x − 3| is not differentiable is:
- A. 1
- B. 2
- C. 0
- D. 3
Answer: A) 1
Explanation: f(x) has sharp turns at x=1 and x=3. In (0,2), only x=1 lies. So 1 point of non-differentiability.
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