If y = (x + √(1 + x²))ⁿ, then (1 + x²)y₂ + x y₁ equals:
If y = (x + √(1 + x²))ⁿ, then (1 + x²)y₂ + x y₁ equals:
- A. n² y
- B. n y
- C. 0
- D. y
Answer: A) n² y
Explanation: y₁ = n(x+√(1+x²))ⁿ⁻¹ (1 + x/√(1+x²)) = n y / √(1+x²). So √(1+x²) y₁ = n y. Squaring and differentiating gives the result n² y.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.