A train from New Delhi to Agra follows a distance-time curve s(t) = t³ − 6t² + 15t + 10 (s in km, t in hours). What is its acceleration at t = 2 hours?
A train from New Delhi to Agra follows a distance-time curve s(t) = t³ − 6t² + 15t + 10 (s in km, t in hours). What is its acceleration at t = 2 hours?
- A. 0 km/h²
- B. 3 km/h²
- C. −6 km/h²
- D. 12 km/h²
Answer: A) 0 km/h²
Explanation: Velocity v(t) = s'(t) = 3t² − 12t + 15. Acceleration a(t) = v'(t) = 6t − 12. At t = 2, a(2) = 12 − 12 = 0.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.