If y = logₑ(√x + 1/√x), then y′ is:
If y = logₑ(√x + 1/√x), then y′ is:
- A. (x−1)/(2x(x+1))
- B. (x+1)/(2x(x−1))
- C. (x−1)/(x(x+1))
- D. (x+1)/(x(x−1))
Answer: A) (x−1)/(2x(x+1))
Explanation: y = log((x+1)/√x) = log(x+1) − ½ log x. y′ = 1/(x+1) − 1/(2x) = (2x − (x+1))/(2x(x+1)) = (x−1)/(2x(x+1)).
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