If y = logₑ(sec x + tan x), then y′ is:
If y = logₑ(sec x + tan x), then y′ is:
- A. sec x
- B. cos x
- C. sec x tan x
- D. cosec x
Answer: A) sec x
Explanation: y′ = (sec x tan x + sec² x)/(sec x + tan x) = sec x (tan x + sec x)/(sec x + tan x) = sec x.
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