imo class 12 continuity and differentiability

If y = sin⁻¹(√(1 − x²)), then dy/dx is:

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If y = sin⁻¹(√(1 − x²)), then dy/dx is:

  • A. −1/√(1−x²)
  • B. 1/√(1−x²)
  • C. −x/√(1−x²)
  • D. x/√(1−x²)

Answer: A) −1/√(1−x²)

Explanation: sin⁻¹(√(1−x²)) = π/2 − sin⁻¹ x. So dy/dx = −1/√(1−x²).

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