If xʸ = eˣ⁻ʸ, then dy/dx is:
If xʸ = eˣ⁻ʸ, then dy/dx is:
- A. log x/(1+log x)²
- B. log x/(1+log x)
- C. x/(1+log x)
- D. 1/(1+log x)
Answer: A) log x/(1+log x)²
Explanation: Take log: y log x = x − y → y(1+log x) = x → y = x/(1+log x). Then dy/dx = [(1+log x) − x·(1/x)]/(1+log x)² = log x/(1+log x)².
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