Find dy/dx for the parametric equations x = a cos θ, y = a sin θ. A. tan θ B. −tan θ C. cot θ D. −cot θ Answer: D) −cot θ Explanation: dx/dθ = −a sin θ. dy/dθ = a cos θ. dy/dx = (dy/dθ) / (dx/dθ) = (a cos θ) / (−a sin θ) = −cot θ.

imo class 12 continuity and differentiability

Find dy/dx for the parametric equations x = a cos θ, y = a sin θ.

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Find dy/dx for the parametric equations x = a cos θ, y = a sin θ.

Answer: D) −cot θ

Explanation: dx/dθ = −a sin θ. dy/dθ = a cos θ. dy/dx = (dy/dθ) / (dx/dθ) = (a cos θ) / (−a sin θ) = −cot θ.