If f(x) = logₑ(logₑ x), then f′(e) is:
If f(x) = logₑ(logₑ x), then f′(e) is:
- A. 1/e
- B. e
- C. 1
- D. 0
Answer: A) 1/e
Explanation: f′(x) = 1/(x log x). At x=e, log e=1, so f′(e)=1/e.
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If f(x) = logₑ(logₑ x), then f′(e) is:
Answer: A) 1/e
Explanation: f′(x) = 1/(x log x). At x=e, log e=1, so f′(e)=1/e.
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