If y = 2^(sin x), find dy/dx.
If y = 2^(sin x), find dy/dx.
- A. 2^(sin x) cos x
- B. 2^(sin x) log(2) cos x
- C. sin x 2^(sin x − 1)
- D. log(2) cos x
Answer: B) 2^(sin x) log(2) cos x
Explanation: Derivative of a^u is a^u log(a) u'. Here a = 2, u = sin x. So dy/dx = 2^(sin x) log(2) cos x.
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