If y = x^(log x), then dy/dx at x = e is:
If y = x^(log x), then dy/dx at x = e is:
- A. 2
- B. e
- C. 1
- D. 2e
Answer: A) 2
Explanation: ln y = (log x)², so y′/y = 2(log x)/x. At x = e, log e = 1 and y = e, hence y′ = e · 2/e = 2.
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