The derivative of logₑ(sin x) w.r.t. √x is:
The derivative of logₑ(sin x) w.r.t. √x is:
- A. (cot x)·2√x
- B. (tan x)·2√x
- C. (cot x)/√x
- D. 2√x cot x
Answer: A) (cot x)·2√x
Explanation: u = log sin x, v = √x. du/dx = cot x, dv/dx = 1/(2√x). du/dv = cot x / (1/(2√x)) = 2√x cot x.
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