The value of ∫₀^π x sin x dx is:
The value of ∫₀^π x sin x dx is:
- A. 0
- B. π
- C. 2π
- D. −π
Answer: B) π
Explanation: Using integration by parts: u = x, dv = sin x dx. ∫ x sin x dx = −x cos x + sin x. From 0 to π: (−π cos π + sin π) − (0 + 0) = −π(−1) = π.
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