What is the value of ∫[0 to 1] 1/(1 + x²) dx?
What is the value of ∫[0 to 1] 1/(1 + x²) dx?
- A. π/2
- B. π/4
- C. π
- D. 1
Answer: B) π/4
Explanation: The anti-derivative is tan⁻¹(x). Evaluating from 0 to 1: tan⁻¹(1) - tan⁻¹(0) = π/4 - 0 = π/4.
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