Evaluate ∫₋₂² |x| dx.
Evaluate ∫₋₂² |x| dx.
- A. 8
- B. 4
- C. 16
- D. 0
Answer: B) 4
Explanation: |x| is even, so ∫₋₂² |x| dx = 2 ∫₀² x dx = 2 · [x²/2]₀² = 2 · 2 = 4.
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Evaluate ∫₋₂² |x| dx.
Answer: B) 4
Explanation: |x| is even, so ∫₋₂² |x| dx = 2 ∫₀² x dx = 2 · [x²/2]₀² = 2 · 2 = 4.
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