Water flows into an overhead tank in Mumbai at a rate of R(t) = 10e^(0.2t) liters/minute. How much water is added to the tank in the first 5 minutes?
Water flows into an overhead tank in Mumbai at a rate of R(t) = 10e^(0.2t) liters/minute. How much water is added to the tank in the first 5 minutes?
- A. 50(e - 1) L
- B. 10(e - 1) L
- C. 25(e - 1) L
- D. 50e L
Answer: A) 50(e - 1) L
Explanation: Volume = ∫[0 to 5] 10e^(0.2t) dt = [10/0.2 e^(0.2t)] from 0 to 5 = 50[e¹ - e⁰] = 50(e - 1) liters.
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