imo class 12 definite integration

Evaluate ∫[-π/2 to π/2] sin⁵x dx.

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Evaluate ∫[-π/2 to π/2] sin⁵x dx.

  • A. 2
  • B. 1
  • C. 0
  • D. π

Answer: C) 0

Explanation: sin⁵x is an odd function because sin⁵(-x) = -sin⁵x. The integral of an odd function from -a to a is 0.

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