Evaluate ∫₀¹ (eˣ + e⁻ˣ)/2 dx.
Evaluate ∫₀¹ (eˣ + e⁻ˣ)/2 dx.
- A. (e − e⁻¹)/2
- B. (e + e⁻¹)/2 − 1
- C. e − e⁻¹
- D. (e² − 1)/2e
Answer: A) (e − e⁻¹)/2
Explanation: ∫ cosh x dx = sinh x. So ∫₀¹ (eˣ+e⁻ˣ)/2 dx = [sinh x]₀¹ = sinh 1 = (e − e⁻¹)/2.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.