The area bounded by y = sin 2x, x = 0, x = π/2 and the x-axis is: A. 0 sq unit B. 1 sq unit C. 2 sq units D. 1/2 sq unit Answer: B) 1 sq unit Explanation: Area = ∫₀^(π/2) |sin 2x| dx. sin 2x ≥ 0 in [0, π/2], so area = ∫₀^(π/2) sin 2x dx = [−1/2 cos 2x]₀^(π/2) = −1/2(−1 − 1) = 1.

imo class 12 definite integration

The area bounded by y = sin 2x, x = 0, x = π/2 and the x-axis is:

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The area bounded by y = sin 2x, x = 0, x = π/2 and the x-axis is:

Answer: B) 1 sq unit

Explanation: Area = ∫₀^(π/2) |sin 2x| dx. sin 2x ≥ 0 in [0, π/2], so area = ∫₀^(π/2) sin 2x dx = [−1/2 cos 2x]₀^(π/2) = −1/2(−1 − 1) = 1.